8x^2+(107-11)x-146=0

Solution for 8x^2+(107-11)x-146=0 equation:

8x^2+(107-11)x-146=0

We add all the numbers together, and all the variables

8x^2+96x-146=0

a = 8; b = 96; c = -146;
Δ = b2-4ac
Δ = 962-4·8·(-146)
Δ = 13888
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{13888}=\sqrt{64*217}=\sqrt{64}*\sqrt{217}=8\sqrt{217}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-8\sqrt{217}}{2*8}=\frac{-96-8\sqrt{217}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+8\sqrt{217}}{2*8}=\frac{-96+8\sqrt{217}}{16}
$